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7w^2-3w-39=0
a = 7; b = -3; c = -39;
Δ = b2-4ac
Δ = -32-4·7·(-39)
Δ = 1101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1101}}{2*7}=\frac{3-\sqrt{1101}}{14} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1101}}{2*7}=\frac{3+\sqrt{1101}}{14} $
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